x^2-4x+68=16

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Solution for x^2-4x+68=16 equation:


Simplifying
x2 + -4x + 68 = 16

Reorder the terms:
68 + -4x + x2 = 16

Solving
68 + -4x + x2 = 16

Solving for variable 'x'.

Reorder the terms:
68 + -16 + -4x + x2 = 16 + -16

Combine like terms: 68 + -16 = 52
52 + -4x + x2 = 16 + -16

Combine like terms: 16 + -16 = 0
52 + -4x + x2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-52' to each side of the equation.
52 + -4x + -52 + x2 = 0 + -52

Reorder the terms:
52 + -52 + -4x + x2 = 0 + -52

Combine like terms: 52 + -52 = 0
0 + -4x + x2 = 0 + -52
-4x + x2 = 0 + -52

Combine like terms: 0 + -52 = -52
-4x + x2 = -52

The x term is -4x.  Take half its coefficient (-2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
-4x + 4 + x2 = -52 + 4

Reorder the terms:
4 + -4x + x2 = -52 + 4

Combine like terms: -52 + 4 = -48
4 + -4x + x2 = -48

Factor a perfect square on the left side:
(x + -2)(x + -2) = -48

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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